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forgot how to calculate for 45s in a box

461 views 13 replies 4 participants last post by  fyerbyrd22 
#1 ·
i just drew a blank on this so im looking for help...how do i calculate for 45s??...i kno that 2 45s equals a square so i would find the area of that square...but how do i transfer that into sq ft?...or is it cubic ft??...this is where i get lost
 
#6 ·
#9 ·
Some pretty general numbers I've found:
a 45 with a 3" hypotenuse (width): other two sides 2 1/8" each: displaces approx .02 cubes @ 12" height
a 45 with a 4 1/4" hypotenuse (width): other two sides 3" each: displaces approx .03 cubes @ 12" height

Check my math though. It's been a while.
 
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